How do you find the domain of $y=log_3 (x-2)$ ?

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Answer 1 · 2016-10-05T07:31:57

The domain is: $D=(2;+oo)$ . See explanation.

The domain of a function is the biggest subset of real numbers set for which the value of function is defined.

Here we have to assume that $x-2>0$ because logarythm is only defined for positive numbers. So we get:

$x-2>0$

$x>2$

If we write this set as an interval we get: $x in (2;+oo)$

How do you find the domain of y=log_3 (x-2)y=log_3 (x-2)?