How do you find the domain of $y = (3x^2)/(x^2+1)$ ?

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How do you find the domain of $y = (3x^2)/(x^2+1)$ ?

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Answer 1 · 2015-06-13T12:57:46

The domain is all the Real $x$ .

Explanation:

The only problem with this function would be a value of $x$ that makes it a division by zero; but the denominator will never become zero!
There is no Real value of $x$ that makes $x^2+1$ equal to zero.

$x^2+1=0$ or $x^2=-1$ NEVER

So this function can accept all the Real $x$ .

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How do you find the domain of $y = (3x^2)/(x^2+1)$ ?

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Explanation:

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How do you find the domain of y = (3x^2)/(x^2+1)y = (3x^2)/(x^2+1)?

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How do you find the domain of $y = (3x^2)/(x^2+1)$ ?