How do you find the domain of (x^2-x-12)^-(1/4)(x2−x−12)−(14)?

1 Answer
Daniel L.
May 12, 2015

The domain is D=(-oo;-3)uu(4;+oo)D=(−∞;−3)∪(4;+∞)

Proof

This function can be written as y=1/(root(4)(x^2-x-12))y=14√x2−x−12.
so the domain is this subset of RR where x^2-x-12>0

After solving given inequality you get the answer. It can also be seen on a graph graph{x^2-x-12 [-13.12, 18.05, -12.99, 2.59]}

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