How do you find the domain of the function $f(x)= x/(x^2+2x-3)$ ?

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Answer 1 · 2015-04-10T02:48:04

Don't take even roots of negative numbers. -- No probhem there are no roots at all.

Don't try9 to divide by $0$ . There is a division, so we need to make sure that $x^2+2x-3$ is not $0$ .

OK, so when is it $0$ ?

Solve $x^2+2x-3 = 0$

$(x+3)(x-1)=0$

$x= -3, 1$

These are the numbers we need to throw out of the domain. So tlhe domain is all real numbers except $-3,1.$

(In interval notation: $(-oo, -3) uu (-3, 1) uu (1,oo)$ )

How do you find the domain of the function f(x)= x/(x^2+2x-3)f(x)= x/(x^2+2x-3)?