How do you find the domain of the function F(x) = (x^2+3x+4)/(x^2+1)^(1/2)F(x)=x2+3x+4(x2+1)12?
1 Answer
May 16, 2018
Explanation:
"the denominator of "f(x)" cannot be zero as this"
"would make "f(x)" undefined"
"note that "sqrt(x^2+1)>0" for all real values of x"
"thus there are no values of x which make the denominator"
"equal to zero"
"domain is "x inRR
graph{(x^2+3x+4)/(sqrt(x^2+1)) [-10, 10, -5, 5]}
