How do you find the domain of the function: f(x) = sqrt(5-3x)?

1 Answer
Gió
Apr 14, 2015

In your function you want to avoid a negative argumet of your square root so you set:
5-3x>=0
getting: x<=5/3
So your domain is all the real x that are less or equal to 5/3.
Note that the negative x made me change the direction of my inequality.
You can have a look substituting values of x to confirm this;
try x=2(>5/3) (which is not acceptable) and x=1(<5/3) (which is ok) to confirm our reasoning.

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