How do you find the domain of the function: $f (x) = \sqrt{4 - 3 x}$ $f(x) = sqrt(4-3x)$ ?

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Answer 1 · 2015-04-19T02:45:51

$x \in$ $x in$ R, $x \leq \frac{4}{3}$ $x<=4/3$

The domain of the function is a field of real numbers x, in which f(x) would be real.

For this to be happen, $4 - 3 x \geq 0$ $4-3x >= 0$

That is $4 \geq 3 x$ $4>=3x$ , Or $\frac{4}{3} \geq x$ $4/3>=x$ .

$x \in$ $x in$ R, $x \leq \frac{4}{3}$ $x <=4/3$

How do you find the domain of the function: f(x)=√4−3xf(x) = sqrt(4-3x)?