How do you find the domain of the following functions f(x)= ln(x-x^2)?

1 Answer
Oct 17, 2015

The domain is the open interval {x in RR:0 < x < 1}=(0,1)

Explanation:

Since the domain of ln(x) is {x in RR:x>0}, it follows that we require x-x^2>0\leftrightarrow x(1-x)>0\leftrightarrow 0 < x < 1. Hence the domain of f(x)=ln(x-x^2) is {x in RR:0 < x < 1}=(0,1).