How do you find the domain of $sqrt(x+3)/((x+8)(x-2))$ ?

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Answer 1 · 2017-02-13T07:16:02

The domain is $x in [-3,2[uu]2,+oo[$

What's under the square root sign is $>=0$ and we cannot divide by $0$

Therefore,

$x+3>=0$ , $=>$ , $x>=-3$

and $x!=-8$

and $x!=2$

Therefore,

the domain is $x in [-3,2[uu]2,+oo[$

How do you find the domain of sqrt(x+3)/((x+8)(x-2))sqrt(x+3)/((x+8)(x-2))?