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How do you find the domain of #sqrt(x+1)/(x-9)#?

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Konstantinos Michailidis

Jun 8, 2016

First of all it should be #x+1>=0=>x>=-1# and #x-9!=0=>x!=9#

Hence the domain is #D=[-1,9)U(9,+oo)#

where #U# is the union of the two sets

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