How do you find the domain of $sqrt(x+1)/(x-9)$ ?

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Answer 1 · 2016-06-08T14:47:04

First of all it should be $x+1>=0=>x>=-1$ and $x-9!=0=>x!=9$

Hence the domain is $D=[-1,9)U(9,+oo)$

where $U$ is the union of the two sets

How do you find the domain of sqrt(x+1)/(x-9)sqrt(x+1)/(x-9)?