How do you find the domain of $sqrt(9-x)$ ?

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Answer 1 · 2017-06-12T18:40:35

Domain: $x <= 9$

Since we have a sqrt, we know that this sqrt must be greater than or equal to $0$ .

$sqrt(9-x) >= 0$

$9-x >= 0$

$9 >= x$

$x <= 9$

How do you find the domain of sqrt(9-x)sqrt(9-x)?