How do you find the domain of $sqrt(3x - 2)$ ?

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Answer 1 · 2017-09-29T11:34:41

Domain: $x>= 2/3 or [ 2/3 , oo)$

$f(x)= sqrt (3x-2)$ . Domain ( eligible input value of x) : Under root

should be $>=0 :. 3x-2 >=0 or 3x >=2 or x >=2/3 :.$

Domain: $x>= 2/3 or [ 2/3 , oo)$

graph{(3x-2)^0.5 [-10, 10, -5, 5]} [Ans]

How do you find the domain of sqrt(3x - 2)sqrt(3x - 2)?