How do you find the domain of $\sqrt[3]{\frac{x + 2}{x - 4}}$ $root3{(x + 2)/(x - 4)}$ ?

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Answer 1 · 2017-04-06T04:46:19

Domain: $x in RR: x!=4$

The function is defined for all real x except when $x=4$

Hence the domain of the function is : $x in RR: x!=4$

This can be seen on the graph of $f(x) = root3((x+2)/(x-4))$ below:

graph{root3((x+2)/(x-4)) [-10, 10, -5, 5]}

How do you find the domain of root3{(x + 2)/(x - 4)}3√x+2x−4root3{(x + 2)/(x - 4)}?