How do you find the domain of $p(x)=x^2+4$ ?

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Answer 1 · 2017-01-03T01:14:03

There are no restrictions in the argument of the function, so the domain is $x in(-ooto+oo)$

The range is another story. Since $x^2>=0$ :
$p(x) in[4to+oo)$
(the square bracket meaning "inclusive")
graph{x^2+4 [-16.28, 15.76, -2.5, 13.52]}

How do you find the domain of p(x)=x^2+4p(x)=x^2+4?