How do you find the domain of #p(x) = (x-2)/3 - 1/(3x)#?

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How do you find the domain of #p(x) = (x-2)/3 - 1/(3x)#?

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Answer 1 · 2018-03-29T08:44:31

#{x in RR | x!=0}#

Explanation:

#p(x)=(x-2)/3-1/(3x)#

From the function we can see that the only value of #x# for which the function is undefined is #x=0#. this would give division by zero, which is undefined.

The domain is therefore all of #RR# except #0#: We can express this as:

#{x in RR | x!=0}#

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How do you find the domain of #p(x) = (x-2)/3 - 1/(3x)#?

1 Answer

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