How do you find the domain of $log(3x^2-4x+5)$ ?

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Answer 1 · 2016-06-20T07:07:00

The domain is $RR$

It must be:

$3x^2-4x+5>0$

let's find the zeroes of the trynomial:

$x=(2+-sqrt(4-15))/3$

Since the expression under square root is negative,
the disequation
$3x^2-4x+5>0$
is verified for all x in $RR$

How do you find the domain of log(3x^2-4x+5)log(3x^2-4x+5)?