How do you find the domain of $g(x)= x^2/(1-x^2)$ ?

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Answer 1 · 2018-03-09T18:29:23

All real values of $x$ except $+-1$

The function $g(x)$ is undefined if the denominator becomes $0$

i.e $1-x^2=0$
so $x^2=1$ , $x=+-1$

How do you find the domain of g(x)= x^2/(1-x^2)g(x)= x^2/(1-x^2)?