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How do you find the domain of #g(x) = sqrt(x^2 - 9)#?

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Apr 9, 2015

Domain in interval notation (-infy, -3]U [3. inf) or,
All real numbers x: x#<=#-3 or x#>=#3.

Domain would be all real numbers x such that #x^2-9# is #>=#0. On solving this inequality, it would be #x^2# #>=#9,
x #>=3#, or -x#>=#3 or x #<=#-3

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