How do you find the domain of $g(x) = sqrt(x^2 - 9)$ ?

Question

How do you find the domain of $g(x) = sqrt(x^2 - 9)$ ?

1 Answer

Impact of this question

1529 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-04-09T18:20:37

Domain in interval notation (-infy, -3]U [3. inf) or,
All real numbers x: x $<=$ -3 or x $>=$ 3.

Domain would be all real numbers x such that $x^2-9$ is $>=$ 0. On solving this inequality, it would be $x^2$ $>=$ 9,
x $>=3$ , or -x $>=$ 3 or x $<=$ -3

Science

Math

Humanities

... and beyond

How do you find the domain of $g(x) = sqrt(x^2 - 9)$ ?

1 Answer

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you find the domain of g(x) = sqrt(x^2 - 9)g(x) = sqrt(x^2 - 9)?

1 Answer

Related questions

Impact of this question

How do you find the domain of $g(x) = sqrt(x^2 - 9)$ ?