How do you find the domain of $g(x) = ln(2 - x - x ^2)$ ?

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Answer 1 · 2018-03-18T21:32:37

$-2< x <1$

The domain of the function are the values of $x$ that give 1 value for $y$ .

For this function, $g(x)$ is valid when $2-x-x^2>0$

$-(x+2)(x-1)>0$

$x+2>0 or -x+1>0$

$x> -2 or x<1$

$-2< x <1$

How do you find the domain of g(x) = ln(2 - x - x ^2)g(x) = ln(2 - x - x ^2)?