How do you find the domain of $g (x) = \frac{10}{4 - 5 x}$ $g(x)=10/(4-5x)$ ?

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How do you find the domain of $g (x) = \frac{10}{4 - 5 x}$ $g(x)=10/(4-5x)$ ?

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Answer 1 · 2015-05-09T19:46:55

The denominator has to be not-zero, so:

$4 - 5 x \neq 0 \Rightarrow x \neq \frac{4}{5}$ $4-5x!=0rArrx!=4/5$ or $(- \infty, \frac{4}{5}) \cup (\frac{4}{5}, + \infty)$ $(-oo,4/5)uu(4/5,+oo)$ .

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How do you find the domain of $g (x) = \frac{10}{4 - 5 x}$ $g(x)=10/(4-5x)$ ?

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