How do you find the domain of $f(x)=(x+5)^(1/2)$ ?

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Answer 1 · 2016-10-17T18:15:11

the domain is -5 to infinity

$f(x)=sqrt(x+5)$
A square root is $>=0$
so $x+5>=0$
Here is a graph of the function
$x>=-5 graph{sqrt(x+5) [-10, 10, -5, 5]}$

How do you find the domain of f(x)=(x+5)^(1/2)f(x)=(x+5)^(1/2)?