How do you find the domain of f(x)=(x^2-4x+4)/(2sin(x))?

1 Answer
Monzur R.
Jan 25, 2017

f(x)=(x^2-4x+4)/(2sinx), x in RR, x!=npi/x!=180n

Explanation:

The domain of a function is all the values of x for which the function is defined. Since the function is a quotient, the only values it isn't defined for is when the denominator is equal to zero.

Since the denominator is a sin function, we know that it will be equal to zero whenever x is a multiple of pi^"c" or 180^"o". So we can write this as x!=npi.

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