How do you find the domain of $f (x) = sqrt (2x - 8)$ ?

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Answer 1 · 2016-05-22T20:06:03

I found $x>=4$

Here you need to avoid a negative argument for your square root, so you impose that:
$2x-8>=0$
or:
$x>=8/2$
$x>=4$

How do you find the domain of f (x) = sqrt (2x - 8)f (x) = sqrt (2x - 8)?