How do you find the domain of $f(x)= 4x^2+1$ ?

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Answer 1 · 2017-04-09T08:07:19

$x inRR$

There are no values of x which make f(x) $color(blue)"undefined"$

$rArr"domain is " x inRR$
graph{4x^2+1 [-10, 10, -5, 5]}

How do you find the domain of f(x)= 4x^2+1f(x)= 4x^2+1?