How do you find the domain of $f(x) = 2 / (1 - x²)$ ?

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Answer 1 · 2017-03-12T13:38:10

The domain of $f(x)$ is $D_f(x)=RR-{-1,1}$

We need

$a^2-b^2=(a+b)(a-b)$

We cannot divide by $0$

The denominator must be different to $0$

$1-x^2=(1+x)(1-x)$

Therefore,

$x!=-1$ and $x!=1$

The domain of $f(x)$ is $D_f(x)=RR-{-1,1}$

How do you find the domain of f(x) = 2 / (1 - x²)f(x) = 2 / (1 - x²)?