How do you find the domain of $5/(x sqrt (x+2))$ ?

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Answer 1 · 2018-06-16T06:13:09

The domain is $x in (-2,0)uu(0,+oo)$

The denominator must be $!=0$

Therefore,

$x!=0$

and

$x+2!=0$ , $=>$ , $x!=-2$

and for the square root sign

$x+2>0$ , $=>$ , $x > -2$

Finally. the domain is $x in (-2,0)uu(0,+oo)$

graph{5/(xsqrt(x+2)) [-20.28, 20.27, -10.14, 10.14]}

How do you find the domain of 5/(x sqrt (x+2))5/(x sqrt (x+2))?