How do you find the domain for $\frac{x}{3 x - 1}$ $x/(3x-1)$ ?

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Answer 1 · 2016-03-02T18:12:33

The domain is $D f = R - {\frac{1}{3}}$ $Df=R-{1/3}$

We must exclude the values that nullify the denominator hence

$3 x - 1 = 0 \Rightarrow x = \frac{1}{3}$ $3x-1=0=>x=1/3$

How do you find the domain for x3x−1x/(3x-1)?