How do you find the domain for $h (c) = \frac{c}{c^{2} + 25}$ $h(c)=c/(c^2+25)$ ?

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Answer 1 · 2017-06-23T16:32:39

The domain is $(- \infty, \infty)$ $(-oo,oo)$ .

Our only restrictions to the domain will occur when the denominator of the fraction equals $0$ $0$ .

We can try to find the domain restrictions then by:

$c^{2} + 25 = 0 \Rightarrow c^{2} = - 25$ $c^2+25=0" "=>" "c^2=-25$

This has no real solutions (we can't take the square root of a negative number), so there are no restrictions on the domain.

Thus, the domain is $(- \infty, \infty)$ $(-oo,oo)$ .

How do you find the domain for h(c)=cc2+25h(c)=c/(c^2+25)?