How do you find the domain for $1/(x-3)$ ?

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Answer 1 · 2016-02-29T09:54:38

everywhere where x - 3 is not zero :)

if x-3 is zero, the function blows up. So anywhere else. it is well-defined. The domain is thus the real axis minus the point x=3

How do you find the domain for 1/(x-3)1/(x-3)?