How do you find the domain and range of #y=sqrt(x-2)#? Algebra Expressions, Equations, and Functions Domain and Range of a Function 1 Answer Konstantinos Michailidis Mar 13, 2018 The domain is #x-2>=0=>x>=2# hence #D_f=[2,+oo)# and the range is #y=sqrt(x-2)>=0=>y>=0# hence #R_f=[0,+oo)# Answer link Related questions How do you determine if (-1, 4), (2, 8), (-1, 5) is a function? What is the domain for #f(x)=2x-4#? What is the domain and range for (3,1), (1,-4), and (2, 8)? What is the domain and range of a linear function? Is domain the independent or dependent variable? How do you find the domain and range of a function in interval notation? How do you find domain and range of a rational function? How do you find domain and range of a quadratic function? How do you determine the domain and range of a function? What is Domain and Range of a Function? See all questions in Domain and Range of a Function Impact of this question 1320 views around the world You can reuse this answer Creative Commons License