How do you find the domain and range of $y=sqrt(3-x)$ ?

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Answer 1 · 2017-01-29T17:20:18

Domain : $x in (-oo, 3]$
Range : $y in [0, oo)$
See the illustrative semi-parabola graph.

$y=sqrt(x-3)>=0$

For y to be real, $x<=3$

graph{sqrt(3-x) [-10, 10, -5, 5]}

How do you find the domain and range of y=sqrt(3-x)y=sqrt(3-x)?