How do you find the domain and range of $y = sqrt(2-x)$ ?

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Answer 1 · 2015-10-02T02:20:34

Refer to explanation

The domain for $y$ is all the real values of $x$ for which

$2-x>=0=>2>=x$ Hence $D(f)=(-oo,2]$

Now for the range we notice that

$y=sqrt(2-x)>=0$ hence $R(f)=[0,+oo)$

How do you find the domain and range of y = sqrt(2-x)y = sqrt(2-x)?