How do you find the domain and range of $Y=(2x-1)^(1/2)$ ?

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Answer 1 · 2017-07-23T13:49:05

The domain is $x in [1/2, +oo)$
The range is $y in [0,+oo)$

Our function is

$y=f(x)=sqrt(2x-1)$

What's under the square root sign is $>=0$

Therefore,

$2x-1>=0$

$x>=1/2$

The domain is $x in [1/2, +oo)$

The minimum value of $y=0$ and the maximum value is $+oo$

The range is $y in [0,+oo)$

graph{sqrt(2x-1) [-6.244, 6.243, -3.12, 3.123]}

How do you find the domain and range of Y=(2x-1)^(1/2)Y=(2x-1)^(1/2)?