How do you find the domain and range of #sqrt(x^2 - 9)#?

Question

How do you find the domain and range of #sqrt(x^2 - 9)#?

1 Answer

Impact of this question

838 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-07-04T06:46:23

Domain = #x#
Range = #x>=3#

Explanation:

The domain is just the input, the variable=s) being changed. In thus case it is just #x#.

The range is the set of values of #x# which can plotted onto a graph. The lowest possible value for #y# is 0. So, #0=sqrt(x^2-9)#, #0=x^2-9#, #9=x^2#, #x=sqrt(9)=3#. #sqrt(3^2-9)=sqrt(9-9)=sqrt(0)=0#.

Science

Math

Humanities

... and beyond

How do you find the domain and range of #sqrt(x^2 - 9)#?

1 Answer

Explanation:

Related questions

Impact of this question