How do you find the domain and range of $h(t) =sqrt(3t+5)$ ?

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Answer 1 · 2016-09-14T11:20:38

Everything under the root should be non-negative or $>=0$

$->3t+5>=0->3t>=-5->t>=-3/5$

There are no restrictions for $t$ getting larger, so domain $[-3/5. oo)$

As the lowest value of the argument can reach $0$ the range is $[0,oo)$

How do you find the domain and range of h(t) =sqrt(3t+5) h(t) =sqrt(3t+5) ?