How do you find the domain and range of $g(x) = 9x + 5$ ?

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Answer 1 · 2017-10-09T15:36:03

$x in RR$ and $g(x) in RR$ or $x in (-oo,+oo)$ and $g(x) in (-oo,+oo)$

The domain is the set of all possible x-values which will make the function "work", and will output real y-values.

So, here we can let $x$ be any real number and our output will be a real number.

The real values of $y$ (in this case $g(x)$ ) is called the range.

Here too, the range can be any real number.

For example-->

Let $x=sqrt2$ (which is a real number)

Then $g(x)=9sqrt2+5$ (which is also a real number)

So for all real values of $x$ we get real values of $g(x)$

Therefore, $x in (-oo,+oo)$ and $g(x) in (-oo,+oo)$

How do you find the domain and range of g(x) = 9x + 5g(x) = 9x + 5?