How do you find the domain and range of $g(x)=8/(3-7x)$ ?

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Answer 1 · 2017-11-20T19:07:15

The domain is $RR-{7/3}$ . The range is $RR-{0}$

The denominator must be $!=0$

Therefore,

$3-7x!=0$

$7x!=3$

$x!=3/7$

So, the domain is $RR-{7/3}$

Let

$y=8/(3-7x)$

$y(3-7x)=8$

$3y-7xy=8$

$7xy=3y-8$

$x=(3y-8)/(7y)$

The same reasoning as above

$y!=0$

The range is $RR-{0}$

graph{8/(3-7x) [-12.66, 12.65, -6.33, 6.33]}

How do you find the domain and range of g(x)=8/(3-7x)g(x)=8/(3-7x)?