How do you find the domain and range of $f(x) = (x+6 )/ (2x+1 )$ ?

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How do you find the domain and range of $f(x) = (x+6 )/ (2x+1 )$ ?

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Answer 1 · 2017-07-18T13:09:31

$f:RR rarr RR, x != -1/2$

Explanation:

To find which values of $x$ don't belong to the domain of $f$ , we have to set the denominator of $f=0$ and solve for $x$

$2x+1=0$

$x=-1/2$

Therefore, $-1/2$ is the only invalid real in the domain. Also, since $x=-1/2$ is an asymptote, we know that $f$ will increase with bound towards $+-oo$ . Therefore, $f$ maps to all $y in RR$ .

Combining these two, we can define

$f:RR rarr RR$

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How do you find the domain and range of $f(x) = (x+6 )/ (2x+1 )$ ?

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Explanation:

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How do you find the domain and range of f(x) = (x+6 )/ (2x+1 ) f(x) = (x+6 )/ (2x+1 )?

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How do you find the domain and range of $f(x) = (x+6 )/ (2x+1 )$ ?