How do you find the domain and range of $f(x)= ln(3x-2)$ ?

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Answer 1 · 2018-08-07T10:44:15

Domain: $x in (2/3, +oo)$
Range: $f(x) in RR$

$f(x) or y=ln(3 x-2)$

Domain: Includes all values of $x$ for which the function is defined.

$f(x)$ is undefined when $3 x-2<=0$ , So, $f(x)$ is defined only

when $3 x-2>0 :. 3 x > 2 or x >2/3$ , Therefore,

domain , $x in (2/3, +oo)$

Range: Includes all values $y$ for which there is some $x$ such

that $y=ln(3x−2)$ . Therefore, range is any real value of $y$

i.e, $f(x) in RR$ .

graph{ln(3 x-2) [-10, 10, -5, 5]} [Ans]

How do you find the domain and range of f(x)= ln(3x-2)f(x)= ln(3x-2)?