How do you find the domain and range of $f(x) = -2 * sqrt(x-3) + 1$ ?

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Answer 1 · 2017-06-20T10:18:31

Domain: $x>=3$ In interval notation : $[3,oo)$
Range: $f(x)<= 1$ . In interval notation : $(-oo,1]$

$f(x) = -2*sqrt(x-3)+1$

Domain: Under root should be $>=0 :. x-3>=0 or x>=3$

Domain: $x>=3$ In interval notation : $[3,oo)$

Range: When $x=3 ; f(x)= 1$ . For $x>3 ; f(x)$ goes on decreasing.

Range: $f(x)<= 1$ . In interval notation : $(-oo,1]$

graph{-2*(x-3)^0.5+1 [-10, 10, -5, 5]} [Ans]

How do you find the domain and range of f(x) = -2 * sqrt(x-3) + 1f(x) = -2 * sqrt(x-3) + 1?