How do you find the domain and range of $f (x) = 2 + e^{x - 5}$ $f(x)= 2+ e^(x-5)$ ?

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Answer 1 · 2015-10-24T20:18:26

Look at the exponential function, then evaluate the range.

The domain or x-value be $(- \infty, \infty)$ $(-oo, oo)$ because the exponential function can accept any value for x.

At $x = - \infty$ $x=-oo$ the exponential will equal zero. So, the lower range is 2.

At $x = \infty$ $x=oo$ the exponential will equal $\infty$ $oo$ . So, the upper range is $\infty$ $oo$ .

In summary:

domain $= (- \infty, \infty)$ $=(-oo, oo)$
range $= [2, \infty)$ $=[2, oo)$

hope that helped

How do you find the domain and range of f(x)=2+ex−5f(x)= 2+ e^(x-5)?