How do you find the domain and range of $arcsin(sin x)$ ?

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Answer 1 · 2017-02-12T05:46:27

Domain and range $arcsin(sinx)$ is $(-oo,oo)$ .

From the definition of $arcsinx$ , which is also described as $sin^(-1)x$ , if $sinx=u$ , we have

$arcsinu=x=>arcsin(sinx)=x$

i.e. $arcsin(sinx)=x$

as domain and range $x$ is $(-oo,oo)$ ,

domain and range $arcsin(sinx)$ is $(-oo,oo)$ .

How do you find the domain and range of arcsin(sin x) arcsin(sin x)?