How do you find the domain and range of $2y^2-x^2 = 8$ ?

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Answer 1 · 2017-10-21T17:30:00

Write in the standard form of hyperbola $(y-k)^2/a^2-(x-h)^2/b^2 = 1$
The range will be $y >= k+ a$ and $y <= k -a$
The domain is $x in RR$

Divide both sides if the given equation by 8:

$y^2/2^2-x^2/(2sqrt2)^2 = 1$

Please observe that $k = 0$ , therefore, the range is:

$y >= 2$ and y <= -2

The domain is $x in RR$

How do you find the domain and range of 2y^2-x^2 = 82y^2-x^2 = 8?