How do you find the domain and range for y= x^2- 6x + 8?

1 Answer
Jim G.
Apr 27, 2017

x inRR

y inRR,y>=-1

Explanation:

Express y in vertex form.

y=(x^2-6x+9)-9+8

color(white)(y)=(x-3)^2-1

y is defined for all real values of x

rArr"domain is " x inRR

(x-3)^2 >=0 AAx

rArr"range is " y inRR,y>=-1
graph{x^2-6x+8 [-10, 10, -5, 5]}

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