How do you find the domain and range for #y= x^2- 6x + 8#?
1 Answer
Apr 27, 2017
Explanation:
Express y in vertex form.
#y=(x^2-6x+9)-9+8#
#color(white)(y)=(x-3)^2-1# y is defined for all real values of x
#rArr"domain is " x inRR#
#(x-3)^2 >=0 AAx#
#rArr"range is " y inRR,y>=-1#
graph{x^2-6x+8 [-10, 10, -5, 5]}
