How do you find the derivitive of Inverse trig function #y=cot(1-2(x)^2)#? Calculus Differentiating Trigonometric Functions Differentiating Inverse Trigonometric Functions 1 Answer bp Jun 17, 2015 #(4x)/(1+4x^4)# Explanation: Given function is y= #cot^-1 2x^2# Cot y= #2x^2#. Now differentiate w.r.t x, to have #sec^2y dy/dx=4x# #dy/dx= (4x)/(1+cot^2 y)= (4x)/(1+4x^4)# Answer link Related questions What is the derivative of #f(x)=sin^-1(x)# ? What is the derivative of #f(x)=cos^-1(x)# ? What is the derivative of #f(x)=tan^-1(x)# ? What is the derivative of #f(x)=sec^-1(x)# ? What is the derivative of #f(x)=csc^-1(x)# ? What is the derivative of #f(x)=cot^-1(x)# ? What is the derivative of #f(x)=(cos^-1(x))/x# ? What is the derivative of #f(x)=tan^-1(e^x)# ? What is the derivative of #f(x)=cos^-1(x^3)# ? What is the derivative of #f(x)=ln(sin^-1(x))# ? See all questions in Differentiating Inverse Trigonometric Functions Impact of this question 1408 views around the world You can reuse this answer Creative Commons License