How do you find the derivative of #y= ln(1 + e^(2x))#?

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How do you find the derivative of #y= ln(1 + e^(2x))#?

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Answer 1 · 2015-04-28T17:11:25

You can use the Chain Rule to derive #ln# first (as it is) and then multiply by the derivative of the argument as:
#y'=1/(1+e^(2x))*2e^(2x)=(2e^(2x))/(1+e^(2x))#

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How do you find the derivative of #y= ln(1 + e^(2x))#?

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