How do you find the derivative of #y = arccos(e^(5x))#? Calculus Differentiating Trigonometric Functions Differentiating Inverse Trigonometric Functions 1 Answer A. S. Adikesavan Apr 10, 2016 #(-5e^(5x))/sqrt(1-e^10x), x<=0#. Explanation: #cos y=e^(5x)#. #(-sin y) y'=5e^(5x)#. #y'=-(5e^(5x))/(1-cos^2y# #=.-(5e^(5x))/(1-e^(10x)# Note that if x>0, #e^(5x)>1#, cos y > 1 and y becomes unreal. Answer link Related questions What is the derivative of #f(x)=sin^-1(x)# ? What is the derivative of #f(x)=cos^-1(x)# ? What is the derivative of #f(x)=tan^-1(x)# ? What is the derivative of #f(x)=sec^-1(x)# ? What is the derivative of #f(x)=csc^-1(x)# ? What is the derivative of #f(x)=cot^-1(x)# ? What is the derivative of #f(x)=(cos^-1(x))/x# ? What is the derivative of #f(x)=tan^-1(e^x)# ? What is the derivative of #f(x)=cos^-1(x^3)# ? What is the derivative of #f(x)=ln(sin^-1(x))# ? See all questions in Differentiating Inverse Trigonometric Functions Impact of this question 2243 views around the world You can reuse this answer Creative Commons License