How do you find the derivative of #y = (3x + 1)^2#?

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How do you find the derivative of #y = (3x + 1)^2#?

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Answer 1 · 2015-11-02T09:30:01

Use chain rule / Expand

Explanation:

Method 1
#y=(3x+1)^2#
Assume the function in the bracket as some other variable say t.
#t = 3x+1#
#dt/dx = 3#
#y = t^2#
#dy/dx = dy/dt * dt/dx#
#=2t*3#
#dy/dx=6(3x+1)#

Method 2
If you can expand everything and find the derivative

#y = (3x+1)^2#
# y = 9x^2+6x+1#
#dy/dx = 18x+6#
#dy/dx = 6(3x+1)#

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How do you find the derivative of #y = (3x + 1)^2#?

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