How do you find the derivative of the function: $y = arccosx + x sqrt(1-x^2)$ ?

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Answer 1 · 2016-01-10T11:31:24

$dy/dx=(-2x^2)/sqrt(1-x^2$

$y=arccos x +xsqrt(1-x^2)$

$dy/dx=-1/sqrt(1-x^2)+1*sqrt(1-x^2)+x*1/(2sqrt(1-x^2))*(-2x)$

after simplification

$dy/dx=(-2x^2)/sqrt(1-x^2$

How do you find the derivative of the function: y = arccosx + x sqrt(1-x^2)y = arccosx + x sqrt(1-x^2)?