How do you find the derivative of the function: $y= arccos( x^7+sqrt5 )$ ?

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Answer 1 · 2016-01-10T03:39:42

$dy/dx=(-7x^6)/sqrt(1-(x^7+sqrt5)^2)$

$d/dx[arccos(u)]=-1/sqrt(1-u^2)*u'$

Thus, if $u=x^7+sqrt5$ :

$d/dx[arccos(x^7+sqrt5)]=-1/sqrt(1-(x^7+sqrt5)^2)*d/dx[x^7+sqrt5]$

$=-1/sqrt(1-(x^7+sqrt5)^2)*7x^6$

$=(-7x^6)/sqrt(1-(x^7+sqrt5)^2)$

How do you find the derivative of the function: y= arccos( x^7+sqrt5 )y= arccos( x^7+sqrt5 )?